3.443 \(\int \frac{A+B x}{x^5 (a+b x)^{3/2}} \, dx\)

Optimal. Leaf size=174 \[ \frac{35 b^3 (9 A b-8 a B)}{64 a^5 \sqrt{a+b x}}+\frac{35 b^2 (9 A b-8 a B)}{192 a^4 x \sqrt{a+b x}}-\frac{35 b^3 (9 A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{64 a^{11/2}}-\frac{7 b (9 A b-8 a B)}{96 a^3 x^2 \sqrt{a+b x}}+\frac{9 A b-8 a B}{24 a^2 x^3 \sqrt{a+b x}}-\frac{A}{4 a x^4 \sqrt{a+b x}} \]

[Out]

(35*b^3*(9*A*b - 8*a*B))/(64*a^5*Sqrt[a + b*x]) - A/(4*a*x^4*Sqrt[a + b*x]) + (9*A*b - 8*a*B)/(24*a^2*x^3*Sqrt
[a + b*x]) - (7*b*(9*A*b - 8*a*B))/(96*a^3*x^2*Sqrt[a + b*x]) + (35*b^2*(9*A*b - 8*a*B))/(192*a^4*x*Sqrt[a + b
*x]) - (35*b^3*(9*A*b - 8*a*B)*ArcTanh[Sqrt[a + b*x]/Sqrt[a]])/(64*a^(11/2))

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Rubi [A]  time = 0.0795249, antiderivative size = 174, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {78, 51, 63, 208} \[ \frac{35 b^2 \sqrt{a+b x} (9 A b-8 a B)}{64 a^5 x}-\frac{35 b^3 (9 A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{64 a^{11/2}}-\frac{35 b \sqrt{a+b x} (9 A b-8 a B)}{96 a^4 x^2}+\frac{7 \sqrt{a+b x} (9 A b-8 a B)}{24 a^3 x^3}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}-\frac{A}{4 a x^4 \sqrt{a+b x}} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*x)/(x^5*(a + b*x)^(3/2)),x]

[Out]

-A/(4*a*x^4*Sqrt[a + b*x]) - (9*A*b - 8*a*B)/(4*a^2*x^3*Sqrt[a + b*x]) + (7*(9*A*b - 8*a*B)*Sqrt[a + b*x])/(24
*a^3*x^3) - (35*b*(9*A*b - 8*a*B)*Sqrt[a + b*x])/(96*a^4*x^2) + (35*b^2*(9*A*b - 8*a*B)*Sqrt[a + b*x])/(64*a^5
*x) - (35*b^3*(9*A*b - 8*a*B)*ArcTanh[Sqrt[a + b*x]/Sqrt[a]])/(64*a^(11/2))

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int \frac{A+B x}{x^5 (a+b x)^{3/2}} \, dx &=-\frac{A}{4 a x^4 \sqrt{a+b x}}+\frac{\left (-\frac{9 A b}{2}+4 a B\right ) \int \frac{1}{x^4 (a+b x)^{3/2}} \, dx}{4 a}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}-\frac{(7 (9 A b-8 a B)) \int \frac{1}{x^4 \sqrt{a+b x}} \, dx}{8 a^2}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}+\frac{7 (9 A b-8 a B) \sqrt{a+b x}}{24 a^3 x^3}+\frac{(35 b (9 A b-8 a B)) \int \frac{1}{x^3 \sqrt{a+b x}} \, dx}{48 a^3}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}+\frac{7 (9 A b-8 a B) \sqrt{a+b x}}{24 a^3 x^3}-\frac{35 b (9 A b-8 a B) \sqrt{a+b x}}{96 a^4 x^2}-\frac{\left (35 b^2 (9 A b-8 a B)\right ) \int \frac{1}{x^2 \sqrt{a+b x}} \, dx}{64 a^4}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}+\frac{7 (9 A b-8 a B) \sqrt{a+b x}}{24 a^3 x^3}-\frac{35 b (9 A b-8 a B) \sqrt{a+b x}}{96 a^4 x^2}+\frac{35 b^2 (9 A b-8 a B) \sqrt{a+b x}}{64 a^5 x}+\frac{\left (35 b^3 (9 A b-8 a B)\right ) \int \frac{1}{x \sqrt{a+b x}} \, dx}{128 a^5}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}+\frac{7 (9 A b-8 a B) \sqrt{a+b x}}{24 a^3 x^3}-\frac{35 b (9 A b-8 a B) \sqrt{a+b x}}{96 a^4 x^2}+\frac{35 b^2 (9 A b-8 a B) \sqrt{a+b x}}{64 a^5 x}+\frac{\left (35 b^2 (9 A b-8 a B)\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b x}\right )}{64 a^5}\\ &=-\frac{A}{4 a x^4 \sqrt{a+b x}}-\frac{9 A b-8 a B}{4 a^2 x^3 \sqrt{a+b x}}+\frac{7 (9 A b-8 a B) \sqrt{a+b x}}{24 a^3 x^3}-\frac{35 b (9 A b-8 a B) \sqrt{a+b x}}{96 a^4 x^2}+\frac{35 b^2 (9 A b-8 a B) \sqrt{a+b x}}{64 a^5 x}-\frac{35 b^3 (9 A b-8 a B) \tanh ^{-1}\left (\frac{\sqrt{a+b x}}{\sqrt{a}}\right )}{64 a^{11/2}}\\ \end{align*}

Mathematica [C]  time = 0.0170232, size = 58, normalized size = 0.33 \[ \frac{b^3 x^4 (9 A b-8 a B) \, _2F_1\left (-\frac{1}{2},4;\frac{1}{2};\frac{b x}{a}+1\right )-a^4 A}{4 a^5 x^4 \sqrt{a+b x}} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)/(x^5*(a + b*x)^(3/2)),x]

[Out]

(-(a^4*A) + b^3*(9*A*b - 8*a*B)*x^4*Hypergeometric2F1[-1/2, 4, 1/2, 1 + (b*x)/a])/(4*a^5*x^4*Sqrt[a + b*x])

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Maple [A]  time = 0.016, size = 147, normalized size = 0.8 \begin{align*} 2\,{b}^{3} \left ({\frac{1}{{a}^{5}} \left ({\frac{1}{{b}^{4}{x}^{4}} \left ( \left ({\frac{187\,Ab}{128}}-{\frac{19\,Ba}{16}} \right ) \left ( bx+a \right ) ^{7/2}+ \left ( -{\frac{643\,Aba}{128}}+{\frac{193\,B{a}^{2}}{48}} \right ) \left ( bx+a \right ) ^{5/2}+ \left ({\frac{765\,Ab{a}^{2}}{128}}-{\frac{223\,B{a}^{3}}{48}} \right ) \left ( bx+a \right ) ^{3/2}+ \left ( -{\frac{325\,A{a}^{3}b}{128}}+{\frac{29\,B{a}^{4}}{16}} \right ) \sqrt{bx+a} \right ) }-{\frac{315\,Ab-280\,Ba}{128\,\sqrt{a}}{\it Artanh} \left ({\frac{\sqrt{bx+a}}{\sqrt{a}}} \right ) } \right ) }-{\frac{-Ab+Ba}{{a}^{5}\sqrt{bx+a}}} \right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)/x^5/(b*x+a)^(3/2),x)

[Out]

2*b^3*(1/a^5*(((187/128*A*b-19/16*B*a)*(b*x+a)^(7/2)+(-643/128*A*b*a+193/48*B*a^2)*(b*x+a)^(5/2)+(765/128*A*b*
a^2-223/48*B*a^3)*(b*x+a)^(3/2)+(-325/128*A*a^3*b+29/16*B*a^4)*(b*x+a)^(1/2))/b^4/x^4-35/128*(9*A*b-8*B*a)/a^(
1/2)*arctanh((b*x+a)^(1/2)/a^(1/2)))-1/a^5*(-A*b+B*a)/(b*x+a)^(1/2))

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(b*x+a)^(3/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 2.53732, size = 836, normalized size = 4.8 \begin{align*} \left [-\frac{105 \,{\left ({\left (8 \, B a b^{4} - 9 \, A b^{5}\right )} x^{5} +{\left (8 \, B a^{2} b^{3} - 9 \, A a b^{4}\right )} x^{4}\right )} \sqrt{a} \log \left (\frac{b x - 2 \, \sqrt{b x + a} \sqrt{a} + 2 \, a}{x}\right ) + 2 \,{\left (48 \, A a^{5} + 105 \,{\left (8 \, B a^{2} b^{3} - 9 \, A a b^{4}\right )} x^{4} + 35 \,{\left (8 \, B a^{3} b^{2} - 9 \, A a^{2} b^{3}\right )} x^{3} - 14 \,{\left (8 \, B a^{4} b - 9 \, A a^{3} b^{2}\right )} x^{2} + 8 \,{\left (8 \, B a^{5} - 9 \, A a^{4} b\right )} x\right )} \sqrt{b x + a}}{384 \,{\left (a^{6} b x^{5} + a^{7} x^{4}\right )}}, -\frac{105 \,{\left ({\left (8 \, B a b^{4} - 9 \, A b^{5}\right )} x^{5} +{\left (8 \, B a^{2} b^{3} - 9 \, A a b^{4}\right )} x^{4}\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{b x + a} \sqrt{-a}}{a}\right ) +{\left (48 \, A a^{5} + 105 \,{\left (8 \, B a^{2} b^{3} - 9 \, A a b^{4}\right )} x^{4} + 35 \,{\left (8 \, B a^{3} b^{2} - 9 \, A a^{2} b^{3}\right )} x^{3} - 14 \,{\left (8 \, B a^{4} b - 9 \, A a^{3} b^{2}\right )} x^{2} + 8 \,{\left (8 \, B a^{5} - 9 \, A a^{4} b\right )} x\right )} \sqrt{b x + a}}{192 \,{\left (a^{6} b x^{5} + a^{7} x^{4}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(b*x+a)^(3/2),x, algorithm="fricas")

[Out]

[-1/384*(105*((8*B*a*b^4 - 9*A*b^5)*x^5 + (8*B*a^2*b^3 - 9*A*a*b^4)*x^4)*sqrt(a)*log((b*x - 2*sqrt(b*x + a)*sq
rt(a) + 2*a)/x) + 2*(48*A*a^5 + 105*(8*B*a^2*b^3 - 9*A*a*b^4)*x^4 + 35*(8*B*a^3*b^2 - 9*A*a^2*b^3)*x^3 - 14*(8
*B*a^4*b - 9*A*a^3*b^2)*x^2 + 8*(8*B*a^5 - 9*A*a^4*b)*x)*sqrt(b*x + a))/(a^6*b*x^5 + a^7*x^4), -1/192*(105*((8
*B*a*b^4 - 9*A*b^5)*x^5 + (8*B*a^2*b^3 - 9*A*a*b^4)*x^4)*sqrt(-a)*arctan(sqrt(b*x + a)*sqrt(-a)/a) + (48*A*a^5
+ 105*(8*B*a^2*b^3 - 9*A*a*b^4)*x^4 + 35*(8*B*a^3*b^2 - 9*A*a^2*b^3)*x^3 - 14*(8*B*a^4*b - 9*A*a^3*b^2)*x^2 +
8*(8*B*a^5 - 9*A*a^4*b)*x)*sqrt(b*x + a))/(a^6*b*x^5 + a^7*x^4)]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x**5/(b*x+a)**(3/2),x)

[Out]

Timed out

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Giac [A]  time = 1.18887, size = 266, normalized size = 1.53 \begin{align*} -\frac{35 \,{\left (8 \, B a b^{3} - 9 \, A b^{4}\right )} \arctan \left (\frac{\sqrt{b x + a}}{\sqrt{-a}}\right )}{64 \, \sqrt{-a} a^{5}} - \frac{2 \,{\left (B a b^{3} - A b^{4}\right )}}{\sqrt{b x + a} a^{5}} - \frac{456 \,{\left (b x + a\right )}^{\frac{7}{2}} B a b^{3} - 1544 \,{\left (b x + a\right )}^{\frac{5}{2}} B a^{2} b^{3} + 1784 \,{\left (b x + a\right )}^{\frac{3}{2}} B a^{3} b^{3} - 696 \, \sqrt{b x + a} B a^{4} b^{3} - 561 \,{\left (b x + a\right )}^{\frac{7}{2}} A b^{4} + 1929 \,{\left (b x + a\right )}^{\frac{5}{2}} A a b^{4} - 2295 \,{\left (b x + a\right )}^{\frac{3}{2}} A a^{2} b^{4} + 975 \, \sqrt{b x + a} A a^{3} b^{4}}{192 \, a^{5} b^{4} x^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(b*x+a)^(3/2),x, algorithm="giac")

[Out]

-35/64*(8*B*a*b^3 - 9*A*b^4)*arctan(sqrt(b*x + a)/sqrt(-a))/(sqrt(-a)*a^5) - 2*(B*a*b^3 - A*b^4)/(sqrt(b*x + a
)*a^5) - 1/192*(456*(b*x + a)^(7/2)*B*a*b^3 - 1544*(b*x + a)^(5/2)*B*a^2*b^3 + 1784*(b*x + a)^(3/2)*B*a^3*b^3
- 696*sqrt(b*x + a)*B*a^4*b^3 - 561*(b*x + a)^(7/2)*A*b^4 + 1929*(b*x + a)^(5/2)*A*a*b^4 - 2295*(b*x + a)^(3/2
)*A*a^2*b^4 + 975*sqrt(b*x + a)*A*a^3*b^4)/(a^5*b^4*x^4)